A whistle producing sound waves of frequencies 9500 Hz and above is approaching a stationary person with speed 
. The velocity of sound in air is 
. If the person can hear frequencies ypte a maximum of 
, the maximum value of 
ypte which he can hear the whistle is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
f’ = f 
10000 = 9500 × 
300 – V = 3 × 95
V = 15 m/s
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Doppler shift in frequency does not depend upon
A source of sound of frequency 450 cycles/sec is moving towards a stationary observer with 34 m/sec…
The wavelength is 120 cm when the source is stationary. If the source is moving with relative veloc…
The frequency of a whistle of an engine is 600 cycles/sec is moving with the speed of 30 m/sec towa…
A source of sound emits waves with frequency f Hz and speed V m/sec. Two observers move away from t…
The source producing sound and an observer both are moving along the direction of propagation of so…